万能方法：

#include<bits/stdc++.h>
using namespace std;
char a[150],b[10]={'O','l','Z','S','b','B','q'},c[10]={'0','1','2','5','6','8','9'};
int main(){
	gets(a);
	for(int i=0;i<strlen(a);i++){
		for(int j=0;j<=6;j++){
			if(a[i]==b[j]) a[i]=c[j];
		}
	}
	cout<<a;
}

#include<bits/stdc++.h> using namespace std; char a[1145]; int main(){ cin>>a; for(int i=0;i<strlen(a);i++) { if(a[i]'O') a[i]='0'; if(a[i]'l') a[i]='1'; if(a[i]'Z') a[i]='2'; if(a[i]'S') a[i]='5'; if(a[i]'b') a[i]='6'; if(a[i]'B') a[i]='8'; if(a[i]=='q') a[i]='9'; } for(int i=0;i<strlen(a);i++) { cout<<a[i]; } return 0; }

高精度

#include<bits/stdc++.h>
using namespace std;
char s1[1000],s2[1000];
int a[10000],b[10000],c[10000],lena,lenb,lenc;
int main()
{
    gets(s1);
    gets(s2);
    lena=strlen(s1);
    lenb=strlen(s2);
    for(int i=0;i<lena;i++){
    	a[i+1]=s1[lena-1-i]-'0';
	}
	for(int i=0;i<lenb;i++){
    	b[i+1]=s2[lenb-1-i]-'0';
	}
	for(int i=1;i<=max(lena,lenb);i++){
		c[i]=b[i]+a[i];
	}
	for(int i=1;i<=max(lena,lenb);i++){
		if(c[i]>9){
			c[i]=c[i]%10;
			c[i+1]++;
		}
	}
	if(c[max(lena,lenb)+1]==0){
		lenc=max(lena,lenb);
	}
	else{
		lenc=max(lena,lenb)+1;
	}
	for(int i=lenc;i>=1;i--){
		cout<<c[i];
	} 
    return 0;
}

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