1 条题解
-
-1
#include <bits/stdc++.h>
using namespace std;
//#define knight 3
struct xy{
int x,y;
}node,Top;
const int dx[4]={1,-1,2,-2};
const int dy[4]={1,-1,2,-2};
int a[401][401];
bool b[401][401];
int n,m;
void bfs(int x,int y,int step){
a[x][y] = step;
b[x][y] = false;
queue Q;
node.x = x;
node.y = y;
Q.push(node);
while (!Q.empty()){
Top=Q.front();
Q.pop();
for (int i=0;i<4;i++)
for (int j=0;j<4;j++)
if (abs(dx[i])!=abs(dy[j])){
int NewX=Top.x+dx[i];
int NewY=Top.y+dy[j];
if (NewX<1||NewX>n||NewY<1||NewY>m) continue;
if (b[NewX][NewY]){
node.x=NewX;
node.y=NewY;
Q.push(node);
b[NewX][NewY] = false;
a[NewX][NewY] = a[Top.x][Top.y]+1;
}
}
}
}
int main(){
memset(b,true,sizeof(b));
memset(a,-1,sizeof(a));
int x,y;
scanf("%d%d%d%d" ,&n ,&m ,&x ,&y );
bfs(x,y,0);
for (int i=1;i<=n;i++){
for (int j=1;j<=m;j++)
printf("%-5d", a[i][j]);
printf("\n");
}
return 0;
}
- 1
信息
- ID
- 1309
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 9
- 标签
- 递交数
- 227
- 已通过
- 25
- 上传者